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Copy pathNextPermutation.kt
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46 lines (42 loc) · 1.21 KB
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/**
* Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers.
*
* If such arrangement is not possible, it must rearrange it as the lowest possible order (ie, sorted in ascending order).
*
* The replacement must be in-place, do not allocate extra memory.
*
* Here are some examples. Inputs are in the left-hand column and its corresponding outputs are in the right-hand column.
* 1,2,3 → 1,3,2
* 3,2,1 → 1,2,3
* 1,1,5 → 1,5,1
*
* Accepted.
*/
class NextPermutation {
fun nextPermutation(nums: IntArray) {
var i = nums.size - 2
while (i >= 0 && nums[i] >= nums[i + 1]) {
i--
}
if (i >= 0) {
var j = nums.size - 1
while (nums[j] <= nums[i]) {
j--
}
swap(nums, i, j)
}
reverse(nums, i + 1, nums.size - 1)
}
private fun swap(nums: IntArray, i: Int, j: Int) {
val tmp = nums[i]
nums[i] = nums[j]
nums[j] = tmp
}
private fun reverse(nums: IntArray, i: Int, j: Int) {
var tmpI = i
var tmpJ = j
while (tmpI < tmpJ) {
swap(nums, tmpI++, tmpJ--)
}
}
}